3x^2+4(x^2-20)=6x^2-16

Solution for 3x^2+4(x^2-20)=6x^2-16 equation:

Simplifying
3x2 + 4(x2 + -20) = 6x2 + -16

Reorder the terms:
3x2 + 4(-20 + x2) = 6x2 + -16
3x2 + (-20 * 4 + x2 * 4) = 6x2 + -16
3x2 + (-80 + 4x2) = 6x2 + -16

Reorder the terms:
-80 + 3x2 + 4x2 = 6x2 + -16

Combine like terms: 3x2 + 4x2 = 7x2
-80 + 7x2 = 6x2 + -16

Reorder the terms:
-80 + 7x2 = -16 + 6x2

Solving
-80 + 7x2 = -16 + 6x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x2' to each side of the equation.
-80 + 7x2 + -6x2 = -16 + 6x2 + -6x2

Combine like terms: 7x2 + -6x2 = 1x2
-80 + 1x2 = -16 + 6x2 + -6x2

Combine like terms: 6x2 + -6x2 = 0
-80 + 1x2 = -16 + 0
-80 + 1x2 = -16

Add '80' to each side of the equation.
-80 + 80 + 1x2 = -16 + 80

Combine like terms: -80 + 80 = 0
0 + 1x2 = -16 + 80
1x2 = -16 + 80

Combine like terms: -16 + 80 = 64
1x2 = 64

Divide each side by '1'.
x2 = 64

Simplifying
x2 = 64

Take the square root of each side:
x = {-8, 8}